Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has 3 links of rates:
- R1 = 512 Kbps
- R2 = 2 Mbps
- R3 = 1 Mbps
What is the throughput for the file transfer (in Kbytes per minute)?
According to me the whole link is equivalent to a 512kbps link and according to that the efficiency = 512*60/8 (KBytes/min).
Is the logic and answer correct, or am I missing something?