I am very new to this subject. If i have a data packet that is 75 bytes long, the frame layer tells me that the size of the packet is 75 bytes, the size of the ethernet frame layer is 14 bytes, the IP header is 20 bytes but the IP datagram has length 61. The TCP segment is 21 in length and the TCP header is 20 bytes in length.
I am trying to figure of where the actual file data is. According to my textbook question, there is 21 byes of file data. If i remove the TCP/IP headers i am left with 22 bytes. Is the extra byte for the port number? leaving 21 byes of file data, this data is all stored in the IP datagram.
I then have to explain why?
There seems to be no information on this in the textbook i have, if i am in the wrong place to be asking this question could someone kindly point me in the correct direction.