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I've been trying to find out what type of packet is 0x5577, based on this page. The following is a snapshot of the source code that indicates this values:

   f = myproto()
    f.timestamp = int(time.time()*1000 - start_time)
    #print f.timestamp
    e = pkt.ethernet()
    e.src=EthAddr("0:0:0:0:0:2")
    e.dst=EthAddr("0:1:0:0:0:1")
    e.type=0x5577  # What ethernet value is this?
    e.payload = f
    msg = of.ofp_packet_out()
    msg.data = e.pack()
    msg.actions.append(of.ofp_action_output(port=2))
    core.openflow.getConnection(src_dpid).send(msg)

I don't also find it in here. I did Google search but without an answer! Has anyone seen this type of ethernet packet before?

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  • Where did you get that number? If is is from the EtherType field of an ethernet frame, it is an unregistered EtherType.
    – Ron Maupin ♦
    Jan 20, 2017 at 20:31
  • @RonMaupin I have updated my post. As you said, can it be unregistered EtherType?
    – steve
    Jan 20, 2017 at 20:36

1 Answer 1

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That is an unregistered EtherType, so, it has no standard meaning or type. It appears that someone just made it up to use for a project. Anyone else could use that value for a different project, and it could mean something else. You will need to ask the person who wrote the code.

EtherTypes are registered with the IEEE, and you can find the registered ones here. IANA also, maintains an unofficial page of EtherTypes.

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