This was an exam question last year, and I was trying to figure out how to get the answer:

A small company is assigned the class C network You need to divide this network to provide subnets for three departments using fixed-length subnetting. The departments are approximately the same size. Show the network and broadcast addresses for each subnet. Show the slash notation. How many hosts are on each subnet? Are the resulting subnets class C networks?

How would you go about doing this? How would you start it?

closed as off-topic by Ron Trunk, Ron Maupin May 13 '17 at 16:14

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "NE is a site for to ask and provide answers about professionally managed networks in a business environment. Your question falls outside the areas our community decided are on topic. Please visit the help center for more details. If you disagree with this closure, please ask on Network Engineering Meta." – Ron Trunk, Ron Maupin
If this question can be reworded to fit the rules in the help center, please edit the question.

  • Unfortunately, all "education, certification, or homework" questions are explicitly off-topic here. By the way, network classes are dead, killed in 1993 by RFCs 1518 and 1519, which defined CIDR (Classless Inter-Domain Routing). Please let them rest in peace. Modern networking doesn't use network classes. – Ron Maupin May 13 '17 at 16:13

Classful subnetting has been deprecated 25 years ago. Any exam that still asks about class A, B or C addresses is dangerously obsolete and should not be taken seriously. I strongly recommend to find an educator who has updated their training material less than a quarter of a century ago...

  • While I agree completely, this ought to be a comment, not an answer. – Ron Trunk May 13 '17 at 11:06
  • Ron: I used to agree, but classful subnetting questions come up so often thati felt that giving a canonical "just don't" answer was becoming appropriate :) – Sander Steffann May 13 '17 at 15:58

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