The IPv4 default route in CIDR notation is
0.0.0.0/0 translated to
For IPv6 the default route in CIDR is
::/0. How is this transated ? Is it as below ?
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The default route has a mask length of 0, so it matches anything. The network address with zero length is actually empty, but usually 0 is used.
It's the same with IPv4 and IPv6, just the notation of the latter has changed - :: expands to as many :0000 as are required to get a 128 bit address, so :: by itself expands to 0000:0000:0000:0000:0000:0000:0000:0000.