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We have to install some network devices (ip camera, max=30) at one of our client sites, so we asked them to give us an IP range.

The client sends the following details,

IP range:= 192.168.0.264/296
Subnet := 255.255.254.0
Gateway := 192.168.0.1

Is this valid? If yes, any details about this will be very helpful?

After some Googling and head scratching, i came to the following conclusion,
IP range := 192.168.1.8 to 192.168.1.40

Is this correct?

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  • 1
    192.168.0.264/296 is not a valid range. Maybe you mean 192.168.0.0/23? I think they mean 192.168.1.10 to 192.168.1.42, but that is a very weird way to write that...
    – user36472
    Commented Jan 25, 2018 at 7:29
  • 1
    This is so wrong in different levels! Period.
    – Maverick
    Commented Jan 25, 2018 at 8:08
  • That is a very odd way of notating a /23 network, but I suppose it does have the benefit of separating the network bits from the host bits. If only there was a standard (RFC 791) way that the client could have written the address range.... :-)
    – ErikF
    Commented Jan 25, 2018 at 15:12
  • @Cown: My bad i included x.x.x.0 and x.x.x.255 in my calculations :-(
    – user82037
    Commented Jan 26, 2018 at 14:27
  • @user82037 yes i did sorry
    – user36472
    Commented Jan 26, 2018 at 14:29

1 Answer 1

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IP range:= 192.168.0.264/296

This is nonsense. The dots are in between octets/bytes and 8 bit can only be 2^8-1=255 max.

With

Subnet := 255.255.254.0

Gateway := 192.168.0.1

the IP range of 192.168.0.0/23 is 192.168.0.1 to 192.168.1.254.

2
  • I know that's not the correct way, but i was considering ip address as <network-id>+<host-id>. By the way we have asked the client to clarify.
    – user82037
    Commented Jan 26, 2018 at 14:36
  • "ip address as <network-id>+<host-id>" - in principle correct, but you need to add the carry to the next more significant octet. Fortunately, IPv6 uses hexadecimal...
    – Zac67
    Commented Jan 26, 2018 at 17:57

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