Basic question about private IP addressing -Class B

Question

Below I will translate from decimal to binary just for the second octet

The theory says the IP range is: 172.16.0.0/12 with addresses ranging between 172.16.0.0-172.31.255.2555

that translates to:
172.00001110.0.0 with mask on the next line
255.11110000.0.0

So the base address for this range is:

172.00000000.0.0 which is 172.0.0.0 and not 172.16.0.0

where is the mistake here ? ☺

Answer 1

You didn't convert correct from decimal to binary. 172.16 = 10101100.00010000