5

I'm not sure this can be done, but figure I'd ask the Gurus here ;)

I have a 2511 router acting as a terminal server for my lab. All the current equipment I have connected to it have serial port baud rates of 9600bps, but now I have a new piece of equipment that has its serial port baud rate set to 115200. For various reasons, i don't want to change this piece of equipment. Is there any way to set the one reverse telnet connection to run at 115200?

4
  • Can you post your current configuration related to your VTY lines? I believe that, as long as you know which VTY line this equipment was connected to, you could change the speed on that line, but I want to test in my lab first. And therefore want to replicate your specific config. Feb 4, 2014 at 20:34
  • *Not VTY lines... just lines. My morning coffee is wearing off. :) For example my 2611 with an NM-16A uses lines 33-48. Feb 4, 2014 at 20:47
  • Here is the current config: gist.github.com/wdennis/8812452 Feb 4, 2014 at 21:11
  • Would you mind if I edited the config into your original post? Feb 4, 2014 at 21:50

1 Answer 1

6

Based on my testing, you would just have to edit the existing line configuration to specify the speed you want on Line 8, for example if that is where you connected your new device. I tested this on a Cisco 2611 with the NM-16A async module.

Existing configuration:

line 1 16
 no exec
 exec-timeout 0 0
 password 7 xxxxxxxxxxxxxxxxx
 login
 transport input all
 stopbits 1

Configuration for device on Line 8 to connect at 115200 bps instead of the default 9600 bps:

line 1 7
 no exec
 exec-timeout 0 0
 password 7 xxxxxxxxxxxxxxxxx
 login
 transport input all
 stopbits 1
line 8
 no exec
 exec-timeout 0 0
 password 7 xxxxxxxxxxxxxxxxx
 login
 transport input all
 speed 115200
 stopbits 1
line 9 16
 no exec
 exec-timeout 0 0
 password 7 xxxxxxxxxxxxxxxxx
 login
 transport input all
 stopbits 1
3
  • Makes sense! Let me give this a try, and hopefully mark as answered! Feb 4, 2014 at 22:55
  • made change, confirmed as correct solution... Thanks!! Feb 4, 2014 at 23:38
  • @WillDennis no problem, glad to help! Feb 5, 2014 at 0:42

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.