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When the first bit reaches the host B, which bit is exit from the host A?

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Each bit between sender and receiver is delayed by the propagation delay - the time it takes to travel the medium.

The rest is pure physics, time = distance / velocity. Since you've got time * bitrate bits on the cable, that's the distance in bits.

Interestingly enough, this bandwidth-delay product is the amount of data that needs to be 'in flight' to saturate the bandwidth of a connection, when acknowledgement is required. With the TCP transport-layer protocol, this is controlled by the receive window.

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