1 - Many networks were allocated prior to the existence of IANA. There's no method to force the recipients to give them back.
2 - there's no point in doing so. This would slightly delay the total exhaustion of IPv4 but not in any meaningful way.
3 - The future is IPv6, delaying IPv4 exhaustion only delay the point where people are forced to use IPv6. This ...
we also see that the fiber is only used till the networking device and not the client nodes like PC or laptop.
That isn't really true. Technically, running fiber to the desktop isn't a problem. However, fiber cables are very delicate and deploying fiber when there's copper you can use is an expensive luxury.
LAN cables made up of copper wires
The root bridge is the switch that 'anchors' the spanning tree: simplified, all switches evaluate their potential paths towards the root bridge and only the 'best' path is kept active, the other links are blocked. The root port of a switch is chosen by its path cost to the root bridge (lower is better), or the lowest priority value, if configured.
If that ...
1.So what can the root bridge do for the ethernet,what is its main function?i know it is important for the network,and all introductions of STP will teach us how to find it,but they don't why do we need to choose the root bridge from all switches?
A spanning tree has to have a root. Here both terms are like in graphs. A root is a tree node which has no ...
Rapid Dual Homing is Korenix's marketing term for redundant meshing of Ethernet with 'rapid' failover (50 ms for ERPS). It encompasses multiple standard protocols:
ERPS V1 (Ethernet Ring Protection Switching V1)
ERPS V2 (Ethernet Ring Protection Switching V2)
RSTP (Rapid Spanning Tree Protocol)
Your "hubs" JetNet 4006f are actually switches as well. "Hub" most commonly refers to repeater hubs only.
If H3 is damage,but the fiber is still ok,will H2 damage too in the future?
No. It is next to impossible for any switch to damage a neighbor switch, especially over fiber.
because H3 is damaged,so H2 will keep sending message,m1, ...
If arrival times are random , then occasionally packets will arrive faster than transmitted and the queue will increase. If that happens often enough, the queue will fill and packets will be dropped. That’s when delay becomes infinite.
i completely understand that why receiver there is 576 bytes but my question is as technology update every after one Minutes then why we can't update that limit
You fundamentally underestimate how hard it is to make a backwards-incompatible change to the Internet.
If you make a backwards-incompatible change to the Internet, EVERY SINGLE DEVICE ON THE ...
You cannot change IPv4's minimum MTU requirement because changing a fundamental requirement will break the Internet.
Specifications exist so that any device design can be fully functional in any network. Imagine an industrial network where one components breaks or needs to be upgraded. The new component's changed specifications don't comply with the rest of ...
There is no problem migrating from an ERL3 to an ER4 because interfaces names between these routers are the same.
After migration, we have to manually create the interface eth3 (because eth3 doesn't exist on EdgeRouter Lite) like this :
set interfaces ethernet eth3 speed auto
set interfaces ethernet eth3 duplex auto
After that, reboot ...
I can't say that this applies to every tunnel imaginable, but this is a general idea how this could work.
A tunnel is set up between an entry point and an exit point. In this case the outer packet will have entry point as a source address and exit point as a destination address. The exit point will receive a packet with itself as a destination address. Thus ...
Encapsulation requires a protocol. Depending on the protocol, an encapsulating packet is uniquely identified by either EtherType (in layer 2), IP protocol number (in layer 3), transport-layer port number (in layer 4), enabling the gateway to handle the packet as required.
The gateway commonly uses additional information from the encapsulating or underlying ...