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Mike Pennington
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The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Thus, his Erlang's definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link. If we make some assumptions about the data network and the type of calls, we can shoe-horn the measurement into a data network.

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks, butnetworks; they can also be adapted for use in data networks

### Question 1
### Question 2
  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigmsee below. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

The formula isto calculate the Erlang capacity (per unit of time)...

Erlang capacity (per unit of time) = C / A

Let's apply this to a 100Mbps Ethernet link, using G.729G.729 voice calls (50pps @ 39200 bits/Gi.729 packete 39200 bps per call).

Maximum ErlangsErlang capacity of a FastEthernet link (using G.729G.729 calls, which are assumed to have 100% of the link):

100000000 bps / 39200 bps = 2551.02 Erlangs

My assumptions about the G.729G.729 packet (ref Cisco's Voice Codec numbers)...

  • PreambleEthernet inter-frame overhead - Preamble, SFDSFD, IFGIFG: 20B20 Bytes
  • EthernetEthernet II header & CRC: 18B18 Bytes
  • IP HdrIPv4 Header: 20B20 Bytes
  • UDP HdrUDP Header: 8B8 Bytes
  • RTP HdrRTP Header: 12B12 Bytes
  • G.729 Voice Payload: 20B20 Bytes

Total G.729G.729 ethernet frame (including all overhead): 98 Bytes

Total bandwidth of G.729 over ethernet (including "invisible"G.729 over ethernet framing overhead):

Note: I took the liberty of modifying Cisco's listed bandwidth of 31.2Kbps per G.729G.729 call, because they leave out the Ethernet framing overhead in that number. The simplest way to illustrate this without making the math more complicated is to include ethernet inter-frame overhead in the G.729G.729 bandwidth consumed.

### Question 3
  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"it depends on how the call is sent over the data network.

The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Thus, his definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link.

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks, but they can be adapted for use in data networks

  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

The formula is

Erlang (per unit of time) = C / A

Let's apply this to a 100Mbps Ethernet link, using G.729 voice calls (50pps @ 39200 bits/G.729 packet).

Maximum Erlangs of a FastEthernet link (using G.729 calls, which are assumed to have 100% of the link):

100000000 / 39200 = 2551.02 Erlangs

My assumptions about the G.729 packet (ref Cisco's Voice Codec numbers)...

  • Preamble, SFD, IFG: 20B
  • Ethernet II header: 18B
  • IP Hdr: 20B
  • UDP Hdr: 8B
  • RTP Hdr: 12B
  • Voice Payload: 20B

Total G.729 ethernet frame (including all overhead): 98 Bytes

Total bandwidth of G.729 over ethernet (including "invisible" ethernet framing overhead):

Note: I took the liberty of modifying Cisco's listed bandwidth of 31.2Kbps per G.729 call, because they leave out the Ethernet framing overhead in that number. The simplest way to illustrate this without making the math more complicated is to include ethernet inter-frame overhead in the G.729 bandwidth consumed.

  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"

The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Erlang's definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link. If we make some assumptions about the data network and the type of calls, we can shoe-horn the measurement into a data network.

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks; they can also be adapted for use in data networks

### Question 1
### Question 2
  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, see below. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

The formula to calculate the Erlang capacity (per unit of time)...

Erlang capacity (per unit of time) = C / A

Let's apply this to a 100Mbps Ethernet link, using G.729 voice calls (i.e 39200 bps per call).

Maximum Erlang capacity of a FastEthernet link (using G.729 calls, which are assumed to have 100% of the link):

100000000 bps / 39200 bps = 2551.02 Erlangs

My assumptions about the G.729 packet (ref Cisco's Voice Codec numbers)...

  • Ethernet inter-frame overhead - Preamble, SFD, IFG: 20 Bytes
  • Ethernet II header & CRC: 18 Bytes
  • IPv4 Header: 20 Bytes
  • UDP Header: 8 Bytes
  • RTP Header: 12 Bytes
  • G.729 Voice Payload: 20 Bytes

Total G.729 ethernet frame (including all overhead): 98 Bytes

Total bandwidth of G.729 over ethernet:

Note: I took the liberty of modifying Cisco's listed bandwidth of 31.2Kbps per G.729 call, because they leave out the Ethernet framing overhead in that number. The simplest way to illustrate this without making the math more complicated is to include ethernet inter-frame overhead in the G.729 bandwidth consumed.

### Question 3
  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... it depends on how the call is sent over the data network.
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Mike Pennington
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  • Q1Q1: How does this apply to data traffic?
  • A1A1: You first have to define what a call is, the bandwidth consumed by a call, and the criteria for blocking a call. Typically you define bandwidth per data call by referencing how much bandwidth is consumed by the Voice Codec in question.
  • Q2Q2: What do we divide by what?
  • A2A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

Maximum Erlangs of a FastEthernet link (using G.729 calls, which are assumed to have 100% of the link):

AssumptionsBandwidth Assumptions:

Total G.729 ethernet frame (including all overhead): 98 Bytes Total

Total bandwidth of G.729 over ethernet (including "invisible" ethernet framing overhead):

Note: I took the liberty of modifying Cisco's listed bandwidth of 31.2Kbps per G.729 call, because they leave out the Ethernet framing overhead in their 31that number.2Kbps per The simplest way to illustrate this without making the math more complicated is to include ethernet inter-frame overhead in the G.729 call figurebandwidth consumed.

  • Q3Q3: What is one Erlang of data traffic?
  • A3A3: It's probably obvious by now... "it depends"
  • Q1: How does this apply to data traffic?
  • A1: You first have to define what a call is, the bandwidth consumed by a call, and the criteria for blocking a call. Typically you define bandwidth per data call by referencing how much bandwidth is consumed by the Voice Codec in question.
  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

Maximum Erlangs of a FastEthernet link (using G.729 calls):

Assumptions:

Total G.729 ethernet frame (including all overhead): 98 Bytes Total bandwidth (including "invisible" ethernet framing overhead):

Note: I took the liberty of modifying Cisco's bandwidth per G.729 call, because they leave out the Ethernet framing overhead in their 31.2Kbps per G.729 call figure.

  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"
  • Q1: How does this apply to data traffic?
  • A1: You first have to define what a call is, the bandwidth consumed by a call, and the criteria for blocking a call. Typically you define bandwidth per data call by referencing how much bandwidth is consumed by the Voice Codec in question.
  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

Maximum Erlangs of a FastEthernet link (using G.729 calls, which are assumed to have 100% of the link):

Bandwidth Assumptions:

Total G.729 ethernet frame (including all overhead): 98 Bytes

Total bandwidth of G.729 over ethernet (including "invisible" ethernet framing overhead):

Note: I took the liberty of modifying Cisco's listed bandwidth of 31.2Kbps per G.729 call, because they leave out the Ethernet framing overhead in that number. The simplest way to illustrate this without making the math more complicated is to include ethernet inter-frame overhead in the G.729 bandwidth consumed.

  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"
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Mike Pennington
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Background

The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Thus, his definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link.

Edit for the OP edit:

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks, but they can be adapted for use in data networks

Q & A


  • Q1: How does this apply to data traffic?
  • A1: You first have to define what a call is, the bandwidth consumed by a call, and the criteria for blocking a call. Typically you define bandwidth per data call by referencing how much bandwidth is consumed by the Voice Codec in question.

  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

For the purposes of a basic Erlang calculation... First, let's assume that voice gets absolute priority across the data network in question. Next, let's define the type of link we're dealing with (because the overhead of a call on Ethernet is different than a Packet-over-SONET link). Finally, let's define some call rejection criteria... the simplest is that the call is rejected if you don't have enough incremental bandwidth for another call (ref the Voice Codec).

After you define those boundaries...

  • C is the total capacity (in bits-per-second) dedicated to voice traffic
  • A is the bandwidth consumed by a single voice call, (ref Voice Codecs)

The formula is

Erlang (per unit of time) = C / A

Let's apply this to a 100Mbps Ethernet link, using G.729 voice calls (50pps @ 39200 bits/G.729 packet).

  • C = 100000000
  • A = 39200

Maximum Erlangs of a FastEthernet link (using G.729 calls):

100000000 / 39200 = 2551.02 Erlangs

Assumptions:

My assumptions about the G.729 packet (ref Cisco's Voice Codec numbers)...

  • Preamble, SFD, IFG: 20B
  • Ethernet II header: 18B
  • IP Hdr: 20B
  • UDP Hdr: 8B
  • RTP Hdr: 12B
  • Voice Payload: 20B

Total G.729 ethernet frame (including all overhead): 98 Bytes Total bandwidth (including "invisible" ethernet framing overhead):

50 G.729 packets/sec * 98 Bytes/G.729 packet * 8 bits/Byte =  39200 bits/second

Note: I took the liberty of modifying Cisco's bandwidth per G.729 call, because they leave out the Ethernet framing overhead in their 31.2Kbps per G.729 call figure.


  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"

The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Thus, his definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link.

Edit for the OP edit:

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks, but they can be adapted for use in data networks

Background

The classical definition of an Erlang was developed in the early 1900s by Professor A.K. Erlang. Thus, his definition does not apply generically to data traffic, because there is no standard definition of a "call" in data traffic, nor is there call-blocking as you would find in a fully-utilized Circuit-Switched link.

Erlang-B and Erlang-C evolved from classical analysis of circuit-switched networks, but they can be adapted for use in data networks

Q & A


  • Q1: How does this apply to data traffic?
  • A1: You first have to define what a call is, the bandwidth consumed by a call, and the criteria for blocking a call. Typically you define bandwidth per data call by referencing how much bandwidth is consumed by the Voice Codec in question.

  • Q2: What do we divide by what?
  • A2: If you're strictly asking about basic Erlang calculations, it's not quite that simple because we have to hamstring the data network into a circuit-switched paradigm. Erlang-B and Erlang-C are a little easier to apply to a data network, because of queuing dynamics that are common to both circuit-switched and data networks.

For the purposes of a basic Erlang calculation... First, let's assume that voice gets absolute priority across the data network in question. Next, let's define the type of link we're dealing with (because the overhead of a call on Ethernet is different than a Packet-over-SONET link). Finally, let's define some call rejection criteria... the simplest is that the call is rejected if you don't have enough incremental bandwidth for another call (ref the Voice Codec).

After you define those boundaries...

  • C is the total capacity (in bits-per-second) dedicated to voice traffic
  • A is the bandwidth consumed by a single voice call, (ref Voice Codecs)

The formula is

Erlang (per unit of time) = C / A

Let's apply this to a 100Mbps Ethernet link, using G.729 voice calls (50pps @ 39200 bits/G.729 packet).

  • C = 100000000
  • A = 39200

Maximum Erlangs of a FastEthernet link (using G.729 calls):

100000000 / 39200 = 2551.02 Erlangs

Assumptions:

My assumptions about the G.729 packet (ref Cisco's Voice Codec numbers)...

  • Preamble, SFD, IFG: 20B
  • Ethernet II header: 18B
  • IP Hdr: 20B
  • UDP Hdr: 8B
  • RTP Hdr: 12B
  • Voice Payload: 20B

Total G.729 ethernet frame (including all overhead): 98 Bytes Total bandwidth (including "invisible" ethernet framing overhead):

50 G.729 packets/sec * 98 Bytes/G.729 packet * 8 bits/Byte =  39200 bits/second

Note: I took the liberty of modifying Cisco's bandwidth per G.729 call, because they leave out the Ethernet framing overhead in their 31.2Kbps per G.729 call figure.


  • Q3: What is one Erlang of data traffic?
  • A3: It's probably obvious by now... "it depends"
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Mike Pennington
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