Timeline for How exactly does CHAP authentication work?
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
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Oct 7, 2021 at 7:34 | history | edited | CommunityBot |
replaced https://tools.ietf.org/html/rfc with https://www.rfc-editor.org/rfc/rfc
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Oct 29, 2018 at 12:37 | history | edited | jonathanjo | CC BY-SA 4.0 |
typo
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S Oct 29, 2018 at 0:30 | history | suggested | Adam | CC BY-SA 4.0 |
corrected example, please see my explanation in comment below
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Oct 28, 2018 at 23:47 | review | Suggested edits | |||
S Oct 29, 2018 at 0:30 | |||||
Oct 28, 2018 at 23:42 | vote | accept | Adam | ||
Oct 28, 2018 at 16:33 | comment | added | Zac67♦ | You're welcome - don't forget to accept the answer if it helped you. | |
Oct 28, 2018 at 10:21 | vote | accept | Adam | ||
Oct 28, 2018 at 10:22 | |||||
Oct 27, 2018 at 21:51 | comment | added | Adam | I found example with pppd logs here. ` [CHAP Challenge id=0x3 <bf2b15282cf4f6672f1b809a251bd731>, name = "HiPer"] [CHAP Response id=0x3 <69cd88a27098f6c3e961f49f0cec74fb>, name = "Sunrise"]` The password was 'freesurf'. Using online hex to MD5 converter following string gave me the same response as in the logs: 036672656573757266bf2b15282cf4f6672f1b809a251bd731. So it seems pppd returns data in hex format. Thanks for the help! | |
Oct 27, 2018 at 16:56 | history | edited | Zac67♦ | CC BY-SA 4.0 |
added 89 characters in body
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Oct 27, 2018 at 16:51 | comment | added | Zac67♦ |
I think 12345 is rather a string than a hex number. The challenge has an arbitrary length, so it's a string. The ID must be the same byte as in the challenge - I've added that to the answer.
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Oct 27, 2018 at 16:16 | vote | accept | Adam | ||
Oct 28, 2018 at 10:21 | |||||
Oct 27, 2018 at 15:46 | comment | added | Adam | Thank you. Could you please confirm if my understanding is correct? Following the example from my question, the string will contain following parts: 0x1 (interpreted as binary data), test, 0x12345 (interpreted as binary data, so there is a mistake in my example, it should be even number of characters) | |
Oct 27, 2018 at 13:49 | history | answered | Zac67♦ | CC BY-SA 4.0 |