0

I have a (hypothetical) network with the following subnet addresses allocated using VLSM:

Allocated addresses

The network address is 150.200.48.0.

According to this site: http://subnet-calculator.org/supernets.php, you can calculate the required supernet mask by taking the length of the sequence of matching bits from left to right:

150.200.048.000: 10010110.11001000.00110000.00000000
...
150.200.052.092: 10010110.11001000.00110100.01011100

Longest matched: xxxxxxxx.xxxxxxxx.xxxxx---.--------

21 bits are matched, so the supernet mask will be /21.

Is this really the correct way of working this out? I assume that this calculation is correct as the supernet mask of /21 can be confirmed on various subnet mask calculators online.

For some reason I'm really struggling to find a good source for this information.

Improve this question
1

1 Answer 1

Reset to default
0

Yes, /21 is the largest supernet you can create containing all those subnets. You need to match the bits from left to right, completely correct.

Improve this answer

Not the answer you're looking for? Browse other questions tagged or ask your own question.